On Fri, Jan 27, 2012 at 9:28 AM, Paul Anton Letnes < paul.anton.let...@gmail.com> wrote:
> > On 27. jan. 2012, at 14:52, Chao YUE wrote: > > > Dear all, > > > > suppose I have a ndarray a: > > > > In [66]: a > > Out[66]: array([0, 1, 2, 3, 4]) > > > > how can use it as 5X1 array without doing a=a.reshape(5,1)? > > Several ways, this is one, although not much simpler. > In [6]: a > Out[6]: array([0, 1, 2, 3, 4]) > > In [7]: a.shape = 5, 1 > > In [8]: a > Out[8]: > array([[0], > [1], > [2], > [3], > [4]]) > > Paul > > I'm assuming your issue with that call to reshape is that you need to know the dimensions beforehand. An alternative is to call: >>> a.reshape(-1, 1) The "-1" allows numpy to "infer" the length based on the given sizes. Another alternative is: >>> a[:, np.newaxis] -Tony
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