Thanks all.

chao

2012/1/27 Tony Yu <tsy...@gmail.com>

>
>
> On Fri, Jan 27, 2012 at 9:28 AM, Paul Anton Letnes <
> paul.anton.let...@gmail.com> wrote:
>
>>
>> On 27. jan. 2012, at 14:52, Chao YUE wrote:
>>
>> > Dear all,
>> >
>> > suppose I have a ndarray a:
>> >
>> > In [66]: a
>> > Out[66]: array([0, 1, 2, 3, 4])
>> >
>> > how can use it as 5X1 array without doing a=a.reshape(5,1)?
>>
>> Several ways, this is one, although not much simpler.
>> In [6]: a
>> Out[6]: array([0, 1, 2, 3, 4])
>>
>> In [7]: a.shape = 5, 1
>>
>> In [8]: a
>> Out[8]:
>> array([[0],
>>       [1],
>>       [2],
>>       [3],
>>       [4]])
>>
>> Paul
>>
>>
> I'm assuming your issue with that call to reshape is that you need to know
> the dimensions beforehand. An alternative is to call:
>
> >>> a.reshape(-1, 1)
>
> The "-1" allows numpy to "infer" the length based on the given sizes.
>
> Another alternative is:
>
> >>> a[:, np.newaxis]
>
> -Tony
>
>
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>
>


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Chao YUE
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