On 04/28/11 14:50, Carnë Draug wrote: > Again, I'm sorry if this is wrong but I'm but a biologist, very little > background on maths. If my understanding is correct NaN == undefined. > If you add something to undefined, shouldn't it be undefined as well? > If so, all values beyond a NaN ocurrence will be NaN in a cumsum. > > Undefined is not the same as 0 which seems to be the behavior you expect.
nan is not 0, that's for sure. But in the nan package, nans are simply neglected, so it behaves as 0 for addition and as 1 for multiplication (sort of). For example: octave:> nansum([[2 5 NaN 7]]) ans = 14 M. ------------------------------------------------------------------------------ WhatsUp Gold - Download Free Network Management Software The most intuitive, comprehensive, and cost-effective network management toolset available today. Delivers lowest initial acquisition cost and overall TCO of any competing solution. http://p.sf.net/sfu/whatsupgold-sd _______________________________________________ Octave-dev mailing list Octave-dev@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/octave-dev
