Am Donnerstag, 28. April 2011, 23:50:28 schrieb Carnë Draug: > On 28 April 2011 22:42, Muhali <muh...@shaw.ca> wrote: > >> octave-3.2.4:11> b = [2 5 NaN 7]; > >> octave-3.2.4:13> cumsum(b) > >> ans = > >> > >> 2 7 NaN NaN > > > > I would expect it to do > > > > octave:> nancumsum(b) > > > > 2 7 7 14
Is this really worth an extra function? It is easily done with b(isnan(b)) = 0; cumsum(b) ------------------------------------------------------------------------------ WhatsUp Gold - Download Free Network Management Software The most intuitive, comprehensive, and cost-effective network management toolset available today. Delivers lowest initial acquisition cost and overall TCO of any competing solution. http://p.sf.net/sfu/whatsupgold-sd _______________________________________________ Octave-dev mailing list Octave-dev@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/octave-dev
