The difference is that in an appserver environment, this will return a
non-finalizing EM by default, but in a Java SE environment, it will
return a finalizing EM by default. See the last bit of my last comment
in OPENJPA-160.

-Patrick

-- 
Patrick Linskey
BEA Systems, Inc. 

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> -----Original Message-----
> From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] 
> Sent: Wednesday, February 28, 2007 10:42 PM
> To: open-jpa-dev@incubator.apache.org
> Subject: Re: svn commit: r513183 - in 
> /incubator/openjpa/trunk: 
> openjpa-kernel/src/main/java/org/apache/openjpa/conf/ 
> openjpa-lib/src/main/java/org/apache/openjpa/lib/conf/ 
> openjpa-persistence/src/main/java/org/apache/openjpa/persistence/
> 
> Hi Patrick,
> 
> I don't quite understand the code that follows. What is the  
> difference between this code and simply defaulting the value to non- 
> finalizing impl?
> 
> Craig
> 
> On Feb 28, 2007, at 10:31 PM, [EMAIL PROTECTED] wrote:
> 
> >          PersistenceUnitInfo pui, Map m) {
> >          PersistenceProductDerivation pd = new  
> > PersistenceProductDerivation();
> >          try {
> > +            // if the BrokerImpl hasn't been specified, 
> switch to the
> > +            // non-finalizing one, since anything claiming 
> to be a  
> > container
> > +            // should be doing proper resource management.
> > +            if (!Configurations.containsProperty(BrokerValue.KEY,
> > +                pui.getProperties())
> > +                && !Configurations.containsProperty 
> > (BrokerValue.KEY, m)) {
> > +                m.put(BrokerValue.KEY,  
> > BrokerValue.NON_FINALIZING_ALIAS);
> > +            }
> > +
> >              ConfigurationProvider cp = pd.load(pui, m);
> >              if (cp == null)
> >                  return null;
> 
> Craig Russell
> Architect, Sun Java Enterprise System http://java.sun.com/products/jdo
> 408 276-5638 mailto:[EMAIL PROTECTED]
> P.S. A good JDO? O, Gasp!
> 
> 

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