Use ShowBoundary instead. This is what I use to view the grid boundary of my spherical coordinate data.
Mike On Mon, 2003-05-19 at 13:02, Wolfgang Dobler wrote: > I have data on a cylindrical grid r1<r<r2, 0<phi<6.07, z1<z<z2. To > visualize them, I do > Mark--Compute(cyl-to-Cartesian)--Unmark > which looks fine; the plots leave a small wedge open, because 6.07 is a > bit less than 2 Pi. > [In order to close this gap, I would need to replicate data from phi=0 for > phi=2 Pi before writing them, or is there a way to tell DX that my third > coordinate is periodic?] > > Now I want to see the bounding box of the grid points. If I plot it > _after_ the coordinate transformation, I get a rectangular box that > encloses all my grid points, which makes some sense. > However, what I really want is the warped representation of my (r,phi,z) > bounding-box. I.e. I would like to get a kind of torus with rectangular > cross section. But if I use ShowBox on the imported data and then > transform from cylindrical to Cartesian, I don't get anything useful. DX > seems to represent the lines that make up the bounding box just by their > end points, which after the transformation just leaves me the small wedge > mentioned above. Even > ShowBox--Tube--Mark--Compute(cyl-to-Cartesian)--Unmark > just showed me the wedge. > > So my question is: Is there a way to interpolate more points into the > lines that come from ShowBox, so I can then transform them and get > something curved? > > > W o l f g a n g > > -- > > ------------------------------------------------------------------------- > | Wolfgang Dobler Phone: ++49/(0)761/3198-224 | > | Kiepenheuer Institute for Solar Physics Fax: ++49/(0)761/3198-111 | > | Schöneckstraße 6 | > | D-79104 Freiburg E-Mail: [EMAIL PROTECTED] | > | Germany http://www.kis.uni-freiburg.de/~dobler/ | > -------------------------------------------------------------------------
