Yes the Tube is inside the 3D field. I had already check that.
Could it be the definition of the grid for the Tube? In the point input, I have [a.x, a.y, b/2] where a is the point where I want the tube to be, and b is the hight of 3D field.In the shape input, I have [0, 0, b/2]. I use b/2 instead of b otherwise the tube desappears completely. If I put a Compute module instead of Map, and put 1 in Compute in order to give data to the tube, it is correctly displayed. So it seems to come from Map... > Do ShowBox on the 3D field and Collect with the original Tube > (pre-Map). I think you'll find the Tube is not completely inside the 3d > bounds, so Map makes everything outside invalid. > > On Jun 23, 2005, at 2:55 AM, Emmanuelle Lafont wrote: > >> I've got a 3D field and I want to visualize only a sample of it, that >> means I define a point, and I see a vertical tube in that point, with >> the >> appropriated colors. >> I've succeed doing this with a vector field (I add vectors on the >> tube), >> but with my 3D field, I only have one half of the tube, the other part >> has >> invalid positions. >> I use the following modules : >> >> 3DField >> | >> Grid() -> Tube() -> Map(input=tube,map=3DField) >> >> Thanks for any help. >> >> >>> Which modules are you running your data through that produces the >>> invalid positions? >>> >>> David >>> >>>> Hi, >>>> >>>> >>>> I'ld like to understand how and why any valid positions become >>>> invalid. >>>> I've searched in the doc, but it's not clear for me. >>>> Is there a way to avoid positions to become invalid? >>>> >>>> >>>> Thanks! >>> >>> >>> -- >>> ...................................................................... >>> .......> David L. Thompson Visualization and >>> Imagery >>> Solutions, Inc. mailto:[EMAIL PROTECTED] 5515 Skyway >>> Drive, Missoula, MT 59804 >>> Phone : (406)756-7472 >> >> >> >> > _______________________________ > Chris Pelkie > Scientific Visualization Producer > 622 Rhodes Hall, Cornell Theory Center > Ithaca, NY 14853 (607) 254-8794
