Can you post your network and data somewhere that someone could grab
a copy and look at it?
David
Yes the Tube is inside the 3D field.
I had already check that.
Could it be the definition of the grid for the Tube?
In the point input, I have [a.x, a.y, b/2] where a is the point where I
want the tube to be, and b is the hight of 3D field.In the shape
input, I have [0, 0, b/2].
I use b/2 instead of b otherwise the tube desappears completely.
If I put a Compute module instead of Map, and put 1 in Compute in order to
give data to the tube, it is correctly displayed. So it seems to come from
Map...
Do ShowBox on the 3D field and Collect with the original Tube
(pre-Map). I think you'll find the Tube is not completely inside the 3d
bounds, so Map makes everything outside invalid.
On Jun 23, 2005, at 2:55 AM, Emmanuelle Lafont wrote:
I've got a 3D field and I want to visualize only a sample of it, that
means I define a point, and I see a vertical tube in that point, with
the
appropriated colors.
I've succeed doing this with a vector field (I add vectors on the
tube),
but with my 3D field, I only have one half of the tube, the other part
has
invalid positions.
I use the following modules :
3DField
|
Grid() -> Tube() -> Map(input=tube,map=3DField)
Thanks for any help.
Which modules are you running your data through that produces the
invalid positions?
David
Hi,
I'ld like to understand how and why any valid positions become
invalid.
I've searched in the doc, but it's not clear for me.
Is there a way to avoid positions to become invalid?
Thanks!
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.......> David L. Thompson Visualization and
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David L. Thompson Visualization and Imagery Solutions, Inc.
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Phone : (406)756-7472
