Martin Bochnig wrote: (MB)

Stefan Teleman wrote: (ST)
>
ST>>At most, you can say that the intersection between KDE e.V. and
ST>>OpenSolaris is not the Null Set, since it contains at least one known
ST>>element. :-)
ST>>
ST>>--Stefan
>>
>
>
MB>However, it depends on how the original unequations are interpreted
MB>(they did not come with any further definitions/assumptions).
MB>
MB> :-)


Stefan,

you cannot simply switch back and forth in regard to what you actually
_mean(t)_ by a very incomplete/isolated specific enum of unequations.
What you write at the top is certainly true for two plain sets, if
evaluated without any context (and that's of course state school level -
set theory).

But if you (indirectly) continue to suggest, I had made a painful
miscalculation, then the following two assumptions must be true:

0) Both "KDE e.V." and "OpenSolaris" are each just a dumb set of their
member's names, nothing else, no logic.
1) You did mean your original unequations *A and *B ...

>Stefan Teleman wrote:
>
*A ST>>>> OpenSolaris != KDE e.V.
*B ST>>>> KDE e.V. != OpenSolaris

... in their actual sense and meaning.
But then go to the end: One single name mismatch would be enough to
assign your original statement the value "true", let's say a different
room-cleaner.
Are you sure that this is, what you originally wanted to express?
That wouldn't be very much.

No, probably not: You certainly meant, "OpenSolaris" and "KDE e.V." are
two completely different and independant entities.
So what you meant was the "All-Quantor"
i.e. statement_~X0~: for all o_Element_O, k_Element_K o!=k
statement_~X1~: for all k_Element_K, o_Element_O k!=o.

And this is how I consequently did interpret *A and *B.
And I have then claimed and formlessly shown, that neither *A, nor *B
can be true in terms of the second way of interpreting them (in the way,
you actually wanted them to be interpreted).
Because your name is both (o_Element_O && k_Element_K) at once, and this
breaks your own universe of
context_relevant_public_statements_from_that_day_on_this_list.

Too many people, admittedly including myself, are frequently not careful
(nor verbose [nor precise]) enough, when (sometimes arbitrarily) using
the inequality sign in public discussion panels.

:)


Martin
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