David Schwartz wrote:
"09dirkd+sRoXWShF8ctVVb4B1PAFTOBEa8diickehnAyEq6KhzLWpQqhqCnylETw\r\n""Drys2uVaAzmRhS6tGJ2fdwPnlSLJrQbHuP938BkyxNhdYN8drfqb\r\n";You appear to have an extra ";" here ---------------------------^ But that should give you a compilation error."-----END RSA PRIVATE KEY-----\r\n";That won't give you a compilation error. But it will cause things not to work. Consider: #include <stdio.h> int main(void) { char *string="This is one line.\r\n"; "This is another.\r\n"; printf("%s", string); } Will produce: This is one line. The ';' after the end of the first line ends the statement. The second string becomes its own statement, which has no effect.
Quite right. In my test program I defined the key string at file scope, and so it does give a compilation error. But if the OP had his string local to a function, it would explain what he was seeing. Tom ______________________________________________________________________ OpenSSL Project http://www.openssl.org User Support Mailing List openssl-users@openssl.org Automated List Manager [EMAIL PROTECTED]
