Thanks guys,
Removing the semi colon fixes the problem !
Cheers :)
On Thu, Oct 2, 2008 at 3:46 AM, Kelly, Tom <[EMAIL PROTECTED]> wrote:
>
>
> David Schwartz wrote:
>
>> "09dirkd+sRoXWShF8ctVVb4B1PAFTOBEa8diickehnAyEq6KhzLWpQqhqCnylETw\r\n"
>>>
>>>> "Drys2uVaAzmRhS6tGJ2fdwPnlSLJrQbHuP938BkyxNhdYN8drfqb\r\n";
>>>>
>>> You appear to have an extra ";" here ---------------------------^
>>> But that should give you a compilation error.
>>>
>>> "-----END RSA PRIVATE KEY-----\r\n";
>>>>
>>>
>> That won't give you a compilation error. But it will cause things not to
>> work. Consider:
>>
>> #include <stdio.h>
>> int main(void)
>> {
>> char *string="This is one line.\r\n";
>> "This is another.\r\n";
>> printf("%s", string);
>> }
>>
>> Will produce:
>>
>> This is one line.
>>
>> The ';' after the end of the first line ends the statement. The second
>> string becomes its own statement, which has no effect.
>>
>
> Quite right. In my test program I defined the key string at file scope,
> and so it does give a compilation error. But if the OP had his string
> local to a function, it would explain what he was seeing.
>
> Tom
>
>
>
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