Hi, The encrypted output is not a NULL terminated string so strlen will not work. >> EVP_DecryptUpdate(&ctx, (unsigned char *)plaintextz, &out_len, (unsigned char *)ciphertext, strlen(ciphertext)); Use the length output from the encryption part.
Thank you very much for the reply. The problem is that the encryption and decryption must be on separate machines. I need a way to take the size of the encrypted message using language function like strlen (). Is there other solution? Regards - re On Sun, May 1, 2011 at 12:27 AM, derleader mail derlea...@abv.bg > wrote: Hi, I'm trying to code a C program that can convert very big number of characters. The problem is that there is an error in decryption. This is the code: //gcc test_Blowfish.c -L/usr/local/ssl/lib/ -lssl -lcrypto -Wall #include #include #include #include #include int main(void) { char plaintext[1024] = "{aaX{aaX57 : {223 : 2323}}{}{}{}{}{}{3535:42424}242424242242424243r23r23r23r23r23r23r3r{}pppa57 : {223 : 2323}}{}{}{}{}{}{3535:42424}242424242242424243r23r23r23r23r23r23r3r{}pppa{aaX57 : {223 : 2323}}{}{}{}{}{}{3535:42424}242424242242424243r23r23r23r23r23r23r3r{}pppa"; char plaintextz[1024]; char ciphertext[1024]= {0,}; char mykey[EVP_MAX_KEY_LENGTH] = "blowfish_key"; char iv[EVP_MAX_IV_LENGTH] = "blowfish"; int tmp_len = 0, in_len, out_len=0; EVP_CIPHER_CTX ctx; //memset(mykey,0,sizeof(mykey)); //memset(iv,0,sizeof(iv)); printf("No encrypt: %s\n", plaintext); printf("No encrypt size: %d\n", strlen(plaintext)); //Encrypt EVP_EncryptInit(&ctx, EVP_bf_cfb(), (unsigned char *)mykey, (unsigned char *)iv); EVP_EncryptUpdate(&ctx, (unsigned char *)ciphertext, &out_len, (unsigned char *)plaintext, strlen(plaintext)); //Block through the mem to be encrypted tmp_len += out_len; EVP_EncryptFinal(&ctx, (unsigned char *) &ciphertext[out_len], &out_len); //Finish any remaining encryption and throw a pad on tmp_len += out_len; printf("Encrypted: %s\n", ciphertext); printf("Encrypted size: %d\n", tmp_len); //Reset memory for Decryption // memset(plaintext,0,sizeof(plaintext)); in_len = tmp_len; out_len = tmp_len = 0; //decrypt EVP_DecryptInit(&ctx, EVP_bf_cfb(), (unsigned char *)mykey, (unsigned char *)iv); EVP_DecryptUpdate(&ctx, (unsigned char *)plaintextz, &out_len, (unsigned char *)ciphertext, strlen(ciphertext)); tmp_len += out_len; EVP_DecryptFinal(&ctx, (unsigned char *)&plaintextz[out_len], &out_len); tmp_len += out_len; //Zero out the pad memset(&plaintext[tmp_len],0,(int)(sizeof(plaintext)) - tmp_len); printf("Decrypted : %s\n", plaintextz); printf("Decrypted size: %d\n", tmp_len); printf("Block Size: %d\n",EVP_CIPHER_CTX_block_size(&ctx)); return 0; } This is the output: [root@localhost test]# ./a.out No encrypt: {aaX{aaX57 : {223 : 2323}}{}{}{}{}{}{3535:42424}242424242242424243r23r23r23r23r23r23r3r{}pppa57 : {223 : 2323}}{}{}{}{}{}{3535:42424}242424242242424243r23r23r23r23r23r23r3r{}pppa{aaX57 : {223 : 2323}}{}{}{}{}{}{3535:42424}242424242242424243r23r23r23r23r23r23r3r{}pppa No encrypt size: 267 Encrypted: �A-�� W =?:�$�i �_�8:�F�wo#�5 � @D�mo��-I ���F�Q�J�#��F�0b� ;�`� C䦱�~6�)ހ�YG �ed�Ӕ�Z%�9!mdvϋ���\���QB��}�N ����@_�W�F�e"� Encrypted size: 267 Decrypted : {aaX{aaX57 : {223 : 2323}}{}{}{}{}{}{3535:42424}242424242242424243r23r23r23r23r23r23r3r{}pppa57 : {223 : 2323}}{}{}{}{}{}{3535:4242 Decrypted size: 131 Block Size: 1 As youy see the decrypted size number is less that the original. Any idea where is the problem?