Here's what the implicit_prefix arg for the IPNetwork constructor does.
Python 2.7.6 (default, Sep 9 2014, 15:04:36)
[GCC 4.2.1 Compatible Apple LLVM 6.0 (clang-600.0.39)] on darwin
Type "help", "copyright", "credits" or "license" for more information.
>>> import netaddr
>>> a = netaddr.IPNetwork("1", implicit_prefix=True)
>>> a
IPNetwork('1.0.0.0/8')
>>> a = netaddr.IPNetwork("1", implicit_prefix=False)
>>> a
IPNetwork('1.0.0.0/32')
>>>
--
Sean M. Collins
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