What is the correct way to override the default servlet context? I am doing
this...
@Component(service = ServletContextHelper.class,property = {
Constants.SERVICE_RANKING+":Integer="+Integer.MAX_VALUE})
@HttpWhiteboardContext(name = "default",path = "/")
public class NoSecurityContextImpl extends ServletContextHelper
{
What I am seeing is if a servlet is registered BEFORE the new default
context it just seems to disappear, anything after gets put in the new
default. When I call HttpServiceRuntime.servletDTOs I see the original
default context with no servlets attached to it and my overridden one with
the servlets that were registered after.
failedServletDTOs,failedServletContextDTOs are empty. If I remove my
override the servlets appear.
What is weird is it looks like the servlet is getting put into the right
context if I read the log correctly ...
Registering
ServletModel{id=ServletModel-4,name='com.candatag.k8s.zoo.servlet.ReadyProbe',urlPatterns=[/osgi/started],contexts=[{WB,OCM-2,default,/}]}
INFO org.ops4j.pax.web.service.spi.servlet.OsgiServletContext -
Unegistering
OsgiServletContext{model=OsgiContextModel{WB,id=OCM-1,name='default',path='/',bundle=org.ops4j.pax.web.pax-web-extender-whiteboard,context=(supplier)}}
as OSGi service for "/" context path
Registering
OsgiServletContext{model=OsgiContextModel{WB,id=OCM-2,name='default',path='/',bundle=com.candatag.web.util,ref={org.osgi.service.http.context.ServletContextHelper}={
service.id=57, osgi.http.whiteboard.context.name=default,
service.bundleid=19, service.scope=bundle, service.ranking=2147483647,
component.name=com.candatag.web.util.zoo.impl.NoSecurityContextImpl,
osgi.http.whiteboard.context.path=/, component.id=22}}} as OSGi service for
"/" context path
Dave
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