(all examples are using /usr/bin/ksh shell)
You could do it this way:
DATE=$(date '+%y%j')
DATE=$((${DATE} - 1))
[ ${#DATE} -eq 4 ] && DATE="0${DATE}"
But you have bigger problems my friend. What happens if the date is 02001
and you subtract 1. The result is 02000 which is invalid. Since you are
in a script that is using the db anyway why not do something like this:
{
sqlplus -s /nolog <<EOF
connect /
set pagesize 0
select to_char(sysdate - 1, 'YYDDD') from dual;
exit;
EOF
} | grep -iv connected | read DATE
Brian P. MacLean
Oracle DBA, OCP8i
"Ball, Terry"
<[EMAIL PROTECTED] To: Multiple recipients of list ORACLE-L
<[EMAIL PROTECTED]>
om> cc:
Sent by: Subject: Sightly OT: Unix scripting
[EMAIL PROTECTED]
om
03/21/02 12:08
PM
Please respond
to ORACLE-L
Environment: Oracle 8.1.6.3 on Solaris 5.8
I am not a Unix Guru by any strech of the imagination, so I can use all the
help I can get. I am trying to write a shell script to execute sqlldr of a
file whose name includes yesterday's 2 digit year and julian day in the
format: file_yyjjj.csv. I can get today's date fine by setting a variable
to be DATE=`date '+%y%j'`
But when I try to get DATE -1 it strips the leading 0 (since it is
currently
02). Does anyone have any suggestions as to how I can retain the leading 0
and still get yesterday's date?
TIA,
Terry
Terry Ball, DBA
Birch Telecom
Work: 816-300-1335
FAX: 816-300-1801
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