I'll show you one way to do it, if you quit calling that a Julian date. :)
( YYDDD is not a Julian date )
$> echo $DATE
2079
$> DATE=$(echo $DATE | awk '{ print substr("0000"$1,length("0000"$1)-4)
}')
$> echo $DATE
02079
Jared
"Ball, Terry" <[EMAIL PROTECTED]>
Sent by: [EMAIL PROTECTED]
03/21/02 11:08 AM
Please respond to ORACLE-L
To: Multiple recipients of list ORACLE-L <[EMAIL PROTECTED]>
cc:
Subject: Sightly OT: Unix scripting
Environment: Oracle 8.1.6.3 on Solaris 5.8
I am not a Unix Guru by any strech of the imagination, so I can use all
the
help I can get. I am trying to write a shell script to execute sqlldr of
a
file whose name includes yesterday's 2 digit year and julian day in the
format: file_yyjjj.csv. I can get today's date fine by setting a variable
to be DATE=`date '+%y%j'`
But when I try to get DATE -1 it strips the leading 0 (since it is
currently
02). Does anyone have any suggestions as to how I can retain the leading
0
and still get yesterday's date?
TIA,
Terry
Terry Ball, DBA
Birch Telecom
Work: 816-300-1335
FAX: 816-300-1801
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