Use HAVING count(name) = 1
Example from our good friend scott.emp
SQL> select job, count(job)
2 from emp
3 group by job;
JOB COUNT(JOB)
--------- ----------
ANALYST 2
CLERK 4
MANAGER 3
PRESIDENT 1
SALESMAN 4
0
6 rows selected.
SQL> i
4 having count(job) = 1
5
SQL> l
1 select job, count(job)
2 from emp
3 group by job
4* having count(job) = 1
SQL> /
JOB COUNT(JOB)
--------- ----------
PRESIDENT 1
-----Original Message-----
Sent: Thursday, August 29, 2002 4:39 PM
To: Multiple recipients of list ORACLE-L
1
Hello guys,
I am baffled by this problem.
I need to fish out the person's name from a list but I only want the
name of the person that occurs once in the list - minus those names that
occurs more than once.
Now, I know about "distinct" and "unique", but this is not what I want.
All I want is to be able to fish out the names of the people who have
only one and exactly only one entry in the list. I do not want the names
of those people who have more than one entry in the list.
Could one of you do me a huge favor give me some hints as to how to
contruct the select statement for this.
Thanks.
ltiu
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Author: ltiu
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Author: Fink, Dan
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