Thanks. On Thursday 29 August 2002 16:47, you wrote: > Use HAVING count(name) = 1 > > Example from our good friend scott.emp > > SQL> select job, count(job) > 2 from emp > 3 group by job; > > JOB COUNT(JOB) > --------- ---------- > ANALYST 2 > CLERK 4 > MANAGER 3 > PRESIDENT 1 > SALESMAN 4 > 0 > > 6 rows selected. > > SQL> i > 4 having count(job) = 1 > 5 > SQL> l > 1 select job, count(job) > 2 from emp > 3 group by job > 4* having count(job) = 1 > SQL> / > > JOB COUNT(JOB) > --------- ---------- > PRESIDENT 1 > > > -----Original Message----- > Sent: Thursday, August 29, 2002 4:39 PM > To: Multiple recipients of list ORACLE-L > 1 > > > Hello guys, > > I am baffled by this problem. > > I need to fish out the person's name from a list but I only want the > name of the person that occurs once in the list - minus those names that > occurs more than once. > > Now, I know about "distinct" and "unique", but this is not what I want. > All I want is to be able to fish out the names of the people who have > only one and exactly only one entry in the list. I do not want the names > of those people who have more than one entry in the list. > > Could one of you do me a huge favor give me some hints as to how to > contruct the select statement for this. > > Thanks. > > ltiu -- Please see the official ORACLE-L FAQ: http://www.orafaq.com -- Author: ltiu INET: [EMAIL PROTECTED]
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