"Post, Ethan" wrote:
>
> Anyone know how to get the owner of a trigger inside a trigger without using
> the stack dump shown here by Tom Kyte which would still need some work to
> get just the owner name.
>
> http://groups.google.com/groups?q=get+table+owner+in+trigger+oracle&hl=en&lr
> =&ie=UTF-8&oe=UTF-8&selm=337efeab.1901213%40newshost&rnum=1
>
> I have the same trigger in same database in different environments
> (DEV,TEST,QA) and the trigger needs to send info using UTL_FILE to different
> directories based on which environment the trigger is in. Refreshes from
> production are automated but the production trigger get put in these other
> environments and I want the same trigger to run everywhere without
> modification. Current plan is to figure out the owner and set the path for
> UTL_FILE based on that.
>
> Any ideas.
>
> Thanks,
> Ethan
create table test (C NUMBER);
create trigger test_trig
before insert on test
is
my_owner varchar2(30);
begin
select a.owner
into my_owner
from v$access a,
v$session s
where s.audsid = sys_context('USERENV', 'SESSIONID')
and s.sid = a.sid
and a.object = 'TEST_TRIG'
create or replace trigger test_trig
before insert on test
declare
my_owner varchar2(30);
begin
select a.owner
into my_owner
from v$access a,
v$session s
where s.audsid = sys_context('USERENV', 'SESSIONID')
and s.sid = a.sid
and a.object = 'TEST_TRIG'
and a.type = 'TRIGGER';
dbms_output.put_line(my_owner);
end;
/
Trigger created.
SQL> set serveroutput on
SQL> insert into test values(1);
ORIOLE
1 row created.
SQL>
--
Regards,
Stephane Faroult
Oriole Software
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Author: Stephane Faroult
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