CREATE TABLE trg_test (p NUMBER);
CREATE OR REPLACE TRIGGER trg_test
BEFORE INSERT -- ...
ON trg_test
DECLARE
ls_owner sys.v_$access.owner%TYPE;
BEGIN
-- dbms_output.enable;
SELECT a.owner
INTO ls_owner
FROM sys.v_$session s
, sys.v_$access a
WHERE s.audsid = SYS_CONTEXT('USERENV', 'SESSIONID')
AND s.sid = a.sid
AND a.object = 'TRG_TEST'
AND a.type = 'TRIGGER'
;
-- dbms_output.put_line('Owner of the trigger is ' || ls_owner);
END;
/
--
Vladimir Begun
The statements and opinions expressed here are my own and
do not necessarily represent those of Oracle Corporation.
Post, Ethan wrote:
Anyone know how to get the owner of a trigger inside a trigger without using
the stack dump shown here by Tom Kyte which would still need some work to
get just the owner name.
http://groups.google.com/groups?q=get+table+owner+in+trigger+oracle&hl=en&lr
=&ie=UTF-8&oe=UTF-8&selm=337efeab.1901213%40newshost&rnum=1
I have the same trigger in same database in different environments
(DEV,TEST,QA) and the trigger needs to send info using UTL_FILE to different
directories based on which environment the trigger is in. Refreshes from
production are automated but the production trigger get put in these other
environments and I want the same trigger to run everywhere without
modification. Current plan is to figure out the owner and set the path for
UTL_FILE based on that.
Any ideas.
Thanks,
Ethan
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--
Author: Vladimir Begun
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