-----Original Message-----
awk and ksh are both interpreting $1.
---------------------------------
Not possible. One or the other will see "$1", but not both. That's the
problem with using quotes instead of assigning things to awk variables -- It
makes reading the stuff confusing.
FWIW, here is what I do:
## See if there is anything to send
COUNT=`awk '/^$/ {next}; END {print NR}' "$PAGE_FILE"`
## If so send it
if [ $COUNT -gt 0 ]; then
PAGER_PERSON=''
cat "${ADMIN_DIR}/who_to_page" | while read LINE; do
PAGER_PERSON="${PAGER_PERSON},${LINE}"
done
## Optional cleanup lines for the intractably paranoid
PAGER_PERSON=`echo "$PAGER_PERSON" | sed 's/[ ]*//g'`
PAGER_PERSON=`echo "$PAGER_PERSON" | sed 's/^,*//g'`
PAGER_PERSON=`echo "$PAGER_PERSON" | sed 's/,,*/,/g'`
if [ -n "$PAGER_PERSON" ]; then
mailx -s "IT IS ALL OVER THE WALLS" "$PAGER_PERSON" < "$PAGE_FILE"
fi
fi
--
Please see the official ORACLE-L FAQ: http://www.orafaq.net
--
Author: Stephen Lee
INET: [EMAIL PROTECTED]
Fat City Network Services -- 858-538-5051 http://www.fatcity.com
San Diego, California -- Mailing list and web hosting services
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