The counts are inclusive:
14706 / 3 means
14,706 14,707 14,708
so you have to skip one then start
again at 14,710.
Yes, 'ela' is the elapsed time in 1/100 of a second.
Regards
Jonathan Lewis
http://www.jlcomp.demon.co.uk
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The Co-operative Oracle Users' FAQ
http://www.jlcomp.demon.co.uk/faq/ind_faq.html
----- Original Message -----
To: "Multiple recipients of list ORACLE-L" <[EMAIL PROTECTED]>
Sent: 14 March 2003 17:04
Here is a part of trace file . I am finding that oracle is trying to
read 8 or 3 or 7 blocks at a time . But block numbers are all
sequential i.e. it will read 3 blocks starting from 14706 and then 8
blocks starting from 14710 ( 14706+3 ). Why it doesn't read 8 blcoks
always it multi_block_read is set to 8 ? Any Idea .
Also what is ela=1 ,does it mean elapsed time is 1 sentisec ?
WAIT #32: nam='db file scattered read' ela= 0 p1=4 p2=14706 p3=3
WAIT #32: nam='db file scattered read' ela= 1 p1=4 p2=14710 p3=8
WAIT #32: nam='db file scattered read' ela= 2 p1=4 p2=14718 p3=8
WAIT #32: nam='db file scattered read' ela= 0 p1=4 p2=14727 p3=3
WAIT #32: nam='db file scattered read' ela= 0 p1=4 p2=14731 p3=7
WAIT #32: nam='db file scattered read' ela= 1 p1=4 p2=14739 p3=3
WAIT #32: nam='db file scattered read' ela= 1 p1=4 p2=14744 p3=8
WAIT #32: nam='db file scattered read' ela= 1 p1=4 p2=129784 p3=8
Thanks
-ak
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Author: Jonathan Lewis
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