Thanks Jonathen ,
But what I am pointing to is , why it is reading 3 blocks first time and
then 8 blocks next time ,  why not 8 blocks  always .
Look at p3 which is no of block read .

-ak


----- Original Message -----
To: "Multiple recipients of list ORACLE-L" <[EMAIL PROTECTED]>
Sent: Friday, March 14, 2003 11:54 AM


>
> The counts are inclusive:
>     14706 / 3 means
>         14,706 14,707 14,708
>  so you have to skip one then start
> again at 14,710.
>
> Yes, 'ela' is the elapsed time in 1/100 of a second.
>
>
> Regards
>
> Jonathan Lewis
> http://www.jlcomp.demon.co.uk
>
> Now available One-day tutorials:
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>
> ----- Original Message -----
> To: "Multiple recipients of list ORACLE-L" <[EMAIL PROTECTED]>
> Sent: 14 March 2003 17:04
>
>
> Here is a part of trace file . I am finding that oracle is trying to
> read 8 or 3 or 7 blocks at a time . But block numbers are all
> sequential i.e. it will read 3 blocks starting from 14706 and then 8
> blocks starting from 14710 ( 14706+3 ). Why it doesn't read 8 blcoks
> always it multi_block_read is set to 8 ? Any Idea .
> Also what is ela=1 ,does it mean elapsed time is 1 sentisec ?
>
>
>
> WAIT #32: nam='db file scattered read' ela= 0 p1=4 p2=14706 p3=3
> WAIT #32: nam='db file scattered read' ela= 1 p1=4 p2=14710 p3=8
> WAIT #32: nam='db file scattered read' ela= 2 p1=4 p2=14718 p3=8
> WAIT #32: nam='db file scattered read' ela= 0 p1=4 p2=14727 p3=3
> WAIT #32: nam='db file scattered read' ela= 0 p1=4 p2=14731 p3=7
> WAIT #32: nam='db file scattered read' ela= 1 p1=4 p2=14739 p3=3
> WAIT #32: nam='db file scattered read' ela= 1 p1=4 p2=14744 p3=8
> WAIT #32: nam='db file scattered read' ela= 1 p1=4 p2=129784 p3=8
>
>
> Thanks
> -ak
>
> --
> Please see the official ORACLE-L FAQ: http://www.orafaq.net
> --
> Author: Jonathan Lewis
>   INET: [EMAIL PROTECTED]
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