Re: SQL HELP!!!

[Viktor]

Jared,

 

I had a temporary brain freeze :), thanks much! I have modified it a bit, and it seems to be working fine! One other small thing. Is there a quick wahy to calculate percentage of web/non-web and vice-versa in the same select after the column "sums"?

 

select distinct id, received_date,  sum(count_web), sum(count_hardcopy)
from (
select distinct id ,
         to_char(received_date, 'YYYY-mm') received_date,
         id||yr||seq_no||ck MSNO,
         CASE WHEN seq_no > 4000 then
         count(*)
         ELSE 0 end Count_WEB,
         CASE WHEN seq_no <=4000 then
         count(*)
         ELSE 0 END Count_HARDCOPY
from t
where id = 'AC'
and received_date between '01/01/2003' and '12/31/2003'
group by id,
         to_char(received_date, 'YYYY-mm'),
         seq_no,
         id||yr||seq_no||ck
)
group by id, received_date

 

Thanks again!

[EMAIL PROTECTED] wrote:

Viktor,

By using an inline view, count_web does indeed become a column.

Did you try the query?

Jared

Viktor <[EMAIL PROTECTED]>  08/26/2003 01:29 PM

To:        [EMAIL PROTECTED], [EMAIL PROTECTED]         cc:                 Subject:        Re: SQL HELP!!!

Jared,
 
Thanks for your fast reply! Sorry if I didn't explain myself clear enough. Unfortunately count_web is not a column, id||yr||seq_no||ck is a combination of 4 columns that make up a primary key. if seq_no >4000, in a id||yr||seq_no||ck row, it's a "web row", if not then it's not. what I would like to see is:
 
ID  Received_date   Non-web count       Web_count
AR 2003-01            0                           4
AR 2003-02            0                           6
AR 2003-0              1                           8
and so forth.....
 
Again thanks for any suggestions you may have!
 
Thanks very much!

[EMAIL PROTECTED] wrote:

I'm not sure I entirely understand the result you are trying to achieve.

Perhaps this will help

select received_date, msno, sum(count_web), hardcopy
from (
select id ,
        to_char(received_date, 'YYYY-mm') received_date,
        id||yr||seq_no||ck MSNO
        CASE WHEN seq_no > 4000 then count(seq_no) ELSE 0 end Count_WEB,
        CASE WHEN seq_no <=4000 then count(seq_no) ELSE 0   END  HARDCOPY
from t
where received_date bet! ween '01/01/2003' and '12/31/2003'
group by id,
 ; to_char(received_date, 'YYYY-mm'),
  sequence_no,
 id||yr||seq_no||ck
)
group by received_date, msno, hardcopy
/

Viktor <[EMAIL PROTECTED]> Sent by: [EMAIL PROTECTED]  08/26/2003 01:59 PM Please respond to ORACLE-L

To:        Multiple recipients of list ORACLE-L <[EMAIL PROTECTED]>        cc:                Subject:        SQL HELP!!!

Hello,
 
I was wondering if someone can help me with a report. I am stuck figuring out what I can do to complete it. Here is what I need to do:
 
for a given date range, i..e. start_date - end_date ('01/01/2003',  '12/31/2003'), I need to count all "web", and "non-web" recor ds. If seq_no > 4000, then it's web, otherwise non-web. seq_no is not ! unique. So it's like 2 different where claused in a single select. Could I somehow use CASE or decode to accomplish this. Here is what I am trying to do in select:
 
select id ,
        to_char(received_date, 'YYYY-mm'),
        id||yr||seq_no||ck MSNO
        CASE WHEN seq_no > 4000 then count(seq_no) ELSE 0 end Count_WEB,
        CASE WHEN seq_no <=4000 then count(seq_no) ELSE 0   END  HARDCOPY
from t
where received_date between '01/01/2003' and '12/31/2003'
group by id,
 to_char(received_date, 'YYYY-mm'),
  sequence_no,
 id||yr||seq_no||ck < BR>/
 
AR 2003-01 AR030023T         0              1
AR 2003-01 AR0200302         0              1
AR 2003-01 AR020047K         0  !            1
AR 2003-01 AR020077N         0              1
 
I would like to show Year-Month once and count all instances of  id||yr||seq_no||ck (primary_key) for that Year-Month, but not to break on it, and unfortunaley it won't let me do it without grouping on seq_no
 
Please advise!!!
 
Any help is greatly appreciated!
 
 

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