select id, received_date,
count(count_non_web) non_web_count,
count(count_web) web_count
from
(select id, to_char(received_date, 'YYYY-mm') received_date,
(case when seq_no <= 4000 then 1 else null end) count_non_web,
(case_when seq_no > 4000 then 1 else null end) count_web
from t
where received_date between '01/01/2003' and '12/31/2003')
group by id,
received_date


HTH, Dave




[EMAIL PROTECTED] wrote:
Jared,
Thanks for your fast reply! Sorry if I didn't explain myself clear enough. Unfortunately count_web is not a column, id||yr||seq_no||ck is a combination of 4 columns that make up a primary key. if seq_no >4000, in a id||yr||seq_no||ck row, it's a "web row", if not then it's not. what I would like to see is:
ID Received_date Non-web count Web_count
AR 2003-01 0 4
AR 2003-02 0 6
AR 2003-0 1 8
and so forth.....
Again thanks for any suggestions you may have!
Thanks very much!








[EMAIL PROTECTED] wrote:


I'm not sure I entirely understand the result you are trying to achieve.

Perhaps this will help

    select received_date, msno, sum(count_web), hardcopy
    from (
    select id ,
             to_char(received_date, 'YYYY-mm') received_date,
             id||yr||seq_no||ck MSNO
             CASE WHEN seq_no > 4000 then count(seq_no) ELSE 0 end
    Count_WEB,
             CASE WHEN seq_no <=4000 then count(seq_no) ELSE 0   END
     HARDCOPY
     from t
    where received_date between '01/01/2003' and '12/31/2003'
    group by id,
    &nbs! p; to_char(received_date, 'YYYY-mm'),
       sequence_no,
      id||yr||seq_no||ck
    )
    group by received_date, msno, hardcopy
    /




Viktor <[EMAIL PROTECTED]> Sent by: [EMAIL PROTECTED]

     08/26/2003 01:59 PM
     Please respond to ORACLE-L

To: Multiple recipients of list ORACLE-L
<[EMAIL PROTECTED]>
cc: Subject: SQL HELP!!!





Hello,
I was wondering if someone can help me with a report. I am stuck
figuring out what I can do to complete it. Here is what I need to do:
for a given date range, i..e. start_date - end_date ('01/01/2003',
'12/31/2003'), I need to count all "web", and "non-web" reco! rds.
If seq_no > 4000, then it's web, otherwise non-web. seq_no is not
unique. So it's like 2 different where claused in a single select.
Could I somehow use CASE or decode to accomplish this. Here is what
I am trying to do in select:
select id ,
to_char(received_date, 'YYYY-mm'),
id||yr||seq_no||ck MSNO
CASE WHEN seq_no > 4000 then count(seq_no) ELSE 0 end
Count_WEB,
CASE WHEN seq_no <=4000 then count(seq_no) ELSE 0 END
HARDCOPY
from t
where received_date between '01/01/2003' and '12/31/2003'
group by id,
to_char(received_date, 'YYYY-mm'),
sequence_no,
id||yr||seq_no||ck !
/
AR 2003-01 AR030023T 0 1
AR 2003-01 AR0200302 0 1
AR 2003-01 AR020047K 0 1
AR 2003-01 AR020077N 0 1
I would like to show Year-Month once and count all instances of
id||yr||seq_no||ck (primary_key) for that Year-Month, but not to
break on it, and unfortunaley it won't let me do it without grouping
on seq_no
Please advise!!! Any help is greatly appreciated!


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