Thank you Midana and Hoppo. It works

On Sat, Mar 12, 2011 at 7:53 PM, Midana Fernandes Sana <mida...@gmail.com>wrote:

> Hi,
> As Hoppo says, many ways to solve it.
> It can be this way:
> SELECT * FROM USER_TAB_COLUMN
> WHERE TAB_NAME IN (SELECT TARGET_TABLE FROM TAB1)
> AND TAB_NAME IN (SELECT SOURCE_TABLE FROM TAB1)
>
> Midana Sana
>
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