Hi Vladimir,
Prefer using of graph functions instead of underlying fields.
So it is better to rewrite query as following
select unionAll($a, $b) let $a = (TRAVERSE out('root for'), out('child of')
FROM [Linda_ID, Shaun_ID, Jeff_ID]), $b = (TRAVERSE in('child of')
FROM [Linda_ID,
Shaun_ID, Jeff_ID])
Best regards,
Artem Orobets
*Orient Technologies the Company behind OrientDB*
2014-07-14 18:39 GMT+03:00 Vladimir Ziankevich <
[email protected]>:
> Of course my picture is just small part. Just demonstrative example.
>
> понедельник, 14 июля 2014 г., 17:43:53 UTC+3 пользователь Andrey Kovalev
> написал:
>
>> According to your picture it should work (theoretically).
>> 'New York islanders' vertex has only incoming edges of type 'root_for'.
>> Then we need to traverse only by outcoming edges of type 'child_of' and
>> finally arrive to 'New York raingers' by incoming connection of type
>> 'root_for'. And we start traversing from 'New York islanders' vertex. If
>> your picture is only a part of a bigger graph then probably query is not
>> valid.
>>
>> On Monday, 14 July 2014 15:36:39 UTC+1, Vladimir Ziankevich wrote:
>>>
>>> But If I travers by V.in_root_for, V.out_root_for does not it mean that
>>> I get all the vertices of the graph rather than subset? Because of this
>>> query has no limitations all the vertices will be traversed.
>>>
>>> --
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