Here are graph example logics.. http://stackoverflow.com/questions/28685205/find-friends-of-friends-with-orientdb-sql
http://stackoverflow.com/questions/29103266/orientdb-query-friend-of-friends-with-more-information-and-filtering if there was a method , the query will be simple select * expand (bothE('IsFriendsWith')[status='approved'].mergeV().bothE('IsFriendsWith')[status='approved'].mergeV()) * from #12:0 where . -- --- You received this message because you are subscribed to the Google Groups "OrientDB" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. For more options, visit https://groups.google.com/d/optout.
