Hi, there is a bothV() method for this, but it seems to be broken, I'm verifying it right now
Thanks Luigi 2015-04-27 2:25 GMT+02:00 Saltık Buğra Avcı <[email protected]>: > > Here are graph example logics.. > > > http://stackoverflow.com/questions/28685205/find-friends-of-friends-with-orientdb-sql > > > http://stackoverflow.com/questions/29103266/orientdb-query-friend-of-friends-with-more-information-and-filtering > > if there was a method , the query will be simple > > select > * expand > (bothE('IsFriendsWith')[status='approved'].mergeV().bothE('IsFriendsWith')[status='approved'].mergeV()) > * > from #12:0 where > > > > > > . > > > > > -- > > --- > You received this message because you are subscribed to the Google Groups > "OrientDB" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to [email protected]. > For more options, visit https://groups.google.com/d/optout. > -- --- You received this message because you are subscribed to the Google Groups "OrientDB" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. For more options, visit https://groups.google.com/d/optout.
