Hi Luigi, that did the trick. I modified it to get nodes in one column and unique:
select distinct(name) from (select expand(bothV) from (select bothV() from (select from (traverse * from #14:0 ) where valid = 1))) Thank you! Roman -- --- You received this message because you are subscribed to the Google Groups "OrientDB" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. For more options, visit https://groups.google.com/d/optout.
