Luigi,

Yes, this helps. Your option #2 is more applicable to my project.

Will OrientDB 3.0 significantly change/improve this use case? I don't want to 
implement this manual edge index if it will become unnecessary in (a few?) 
weeks.

Thanks!

-- John

> On Mar 16, 2017, at 07:24, Luigi Dell'Aquila <[email protected]> 
> wrote:
> 
> Hi John,
> 
> you have two alternatives:
> 
> 1) use OrientVertex.countEdges() to check which of the two vertices has a 
> smaller number of edges. This approach is good if you know that at most one 
> is a supernode
> 
> 2) if you know that both vertices can be supernodes, then the only efficient 
> way to find the edge is to define and index on edge(out, in) and do the 
> indexed query directly
> 
> I hope it helps
> 
> Thanks
> 
> Luigi
> 
> 
> 2017-03-16 11:18 GMT+01:00 John J. Szucs <[email protected]>:
>> I need to *very quickly* find the edges that directly connect two specified 
>> vertices, using either a SQL query, the Java API, or a combination of the 
>> two. If it helps, at this point in the program, I know for a fact that the 
>> two vertices are adjacent. What I'm trying to determine is how they are 
>> adjacent.
>> 
>> The OrientVertex.getEdges(OrientVertex, Direction, String ...) extension to 
>> the Blueprints API does what I need to do functionally, but it can be quite 
>> slow if the first vertex has many edges. Looking into the source code, I 
>> found that this is because this method essentially gets *all* of the edges 
>> from the first vertex that match the direction and label criteria and then 
>> checks if they are adjacent (connect to) the second vertex.
>> 
>> I have struggled with this for days. Does anyone have a better/faster 
>> approach?
>> 
>> Thanks!
>> 
>> -- John
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