Hi forest,

I have done this several times in order to simulate springs. If you have the 
3D trajectory, you will also have or you can compute the tangent vector (the 
one that follows it). For every point in the trajectory, you place a 
point "r" units away from it and in a perpendicular direction from the 
tangent. Then you can rotate that point about the tangent axis in order to 
get the rest of the points of the ring. You can repeat this procedure as many 
times as rings you want.

But now that I realize, maybe that feature is already implemented in 
osgModeling by Wang Rui (http://code.google.com/p/osgmodeling/)

Regards,

Alberto

El Viernes 26 Junio 2009ES 08:05:52 forest escribió:
> hi all,
>        I know this problem is not so related to OSG, but there is no better
> place I can find. What I want to draw is to draw a three-dimensional pipe
> from a 3d curve with a given radius.The "pipe" I mean is alike a
> cylinder,but it is bent. any ideas? thanks in advance.
>        best regards
>  forest


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