> > This is pretty non-responsive to the question. I know how event
> > processing works. I have event handlers for this form. I have a
> > normal event processing loop.
>
> It's not always clear what is or is not obvious. Based on your
> description, I don't see why it's not working. I'd use the debugger to
> see whether you're actually getting a frmOpenEvent for the form you're
> popping up and if so, that it is indeed being passed into
> FrmDispatchEvent. I'd also verify that you're calling
> FrmSetEventHandler for this form (again, using the debugger). Beyond
> that, I don't know.
I have already verified that I am not getting the frmOpenEvent. I
also have the following set for my event handler for this form:
case frmGraph:
FrmSetEventHandler(form, (FormEventHandlerPtr) frmMyFormH);
break;
This is set in the event loop as it should be. That is what is so
strange about this. The form will pop up, as expected, if I issue a
FrmPopupForm(frmMyForm) outside of the loop in question. Only when
inside the loop where it depends on the CheckEscape() does it fail to
open properly. Somehow I am blocking the event from being processed.
>
>
> --
> For information on using the Palm Developer Forums, or to unsubscribe,
> please see http://www.palm.com/devzone/mailinglists.html
>
--
-----------------------------------------------------------------
Discussion Group: http://www.halcyon.com/ipscone/wwwboard/
Protect your constitutional rights. Your favorite one may be next!
-----------------------------------------------------------------
--
For information on using the Palm Developer Forums, or to unsubscribe, please see
http://www.palm.com/devzone/mailinglists.html
