Or how about this:
Byte swap_byte(Byte b)
{
static Byte swapped_nibble[16] = {
0x00, 0x80, 0x40, 0xC0,
0x20, 0xA0, 0x60, 0xe0,
0x10, 0x90, 0x50, 0xd0,
0x30, 0xb0, 0x70, 0xf0
};
return swapped_nibble[b & 0x0f] + (swapped_nibble[(b & 0xf0) >> 4] >>
4);
}
-- bob
====================
Robert Herold (650) 627-3302
Webvan Group, Inc (650) 627-3948 (fax)
310 Lakeside Drive [EMAIL PROTECTED]
Foster City, CA 94404 www.webvan.com
-----Original Message-----
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]]
Sent: Friday, May 12, 2000 12:00 PM
To: Palm Developer Forum
Subject: Re: Byte order
This function seems like its doing a lot of work, what about something like
this instead:
Byte swap_byte(Byte byOld)
{
Byte byNew = 0;
if (byOld & 0x01) { byNew |= 0x80; }
if (byOld & 0x02) { byNew |= 0x40; }
if (byOld & 0x04) { byNew |= 0x20; }
if (byOld & 0x08) { byNew |= 0x10; }
if (byOld & 0x10) { byNew |= 0x08; }
if (byOld & 0x20) { byNew |= 0x04; }
if (byOld & 0x40) { byNew |= 0x02; }
if (byOld & 0x80) { byNew |= 0x01; }
return byNew;
}
In a message dated 5/12/00 12:32:49 PM Eastern Daylight Time,
[EMAIL PROTECTED] writes:
<< Byte swap_byte(Byte old_byte){
Byte new_byte;
Byte working_byte[8];
int i;
new_byte=0x00; // zero out new_byte
for(i=0;i<8;i++)
working_byte[i]=0x00; // zero out working bytes
working_byte[0]=(old_byte << 7); // bit 1
working_byte[1]=(old_byte >> 1); // bit 2
working_byte[1]=(working_byte[1] << 7);
working_byte[1]=(working_byte[1] >> 1);
working_byte[2]=(old_byte >> 2); // bit 3
working_byte[2]=(working_byte[2] << 7);
working_byte[2]=(working_byte[2] >> 2);
working_byte[3]=(old_byte >> 3); // bit 4
working_byte[3]=(working_byte[3] << 7);
working_byte[3]=(working_byte[3] >> 3);
working_byte[4]=(old_byte >> 4); // bit 5
working_byte[4]=(working_byte[4] << 7);
working_byte[4]=(working_byte[4] >> 4);
working_byte[5]=(old_byte >> 5); // bit 6
working_byte[5]=(working_byte[5] << 7);
working_byte[5]=(working_byte[5] >> 5);
working_byte[6]=(old_byte >> 6); // bit 7
working_byte[6]=(working_byte[6] << 7);
working_byte[6]=(working_byte[6] >> 6);
working_byte[7]=(old_byte >> 7); // bit 8
for(i=0;i<8;i++){
new_byte=(new_byte | working_byte[i]);
} // end for loop
return(new_byte);
} // end function >>
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