Hi,
Someone post this routine below to convert a Hex to an Int. It worked fine,
but it seem to convert only the first 4 digits supplied.
Say i wish to convert 35A4E900 , it only converts 35A4. Anyone any idea
how to get it to convert all 8 chars?
int StrHexToInt(const char* pszHex)
{
int nResult = 0;
for (int i = 0; *pszHex && (i < (sizeof(int) << 1)); i++)
{
nResult <<= 4;
char c = *pszHex++;
if ((c & 0xF0) == 0x30)
nResult |= (c & 0x0F);
else
nResult |= ((c & 0x0F) + 9);
}
return (nResult);
}
Thanks!
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