On Wed, 25 Apr 2001, Fergal Moran wrote:
> > I need to know the remainder of (number1 / number2) where
> > number1 and
> > number2 there are doubles.
> >
> > Is there same function for that in the codewarrior 7.0 ?
> >
> standard C/C++ - (number1 % number2) - % = modulus operator
>
> Fergal..
But number1 & number2 are doubles?? Maybe he means decimal part:
number1/number2-(Long)(number1/number2)
or something like that...
-DR
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