> On Wed, 25 Apr 2001, Fergal Moran wrote:
> > > I need to know the remainder of (number1 / number2) where
> > > number1 and
> > > number2 there are doubles.
> > > Is there same function for that in the codewarrior 7.0 ?
> > standard C/C++ - (number1 % number2) - % = modulus operator
> > Fergal..
> That won't work very well for doubles.
>
> AFAIK there is no simple solution.
>
>
Whoops - I'll read more carefully in the future!!
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