> From: Tan Kuan Eeik
>
> I 've mark the link where error occurs and here 's the error and the code.
> This is caused by trying to access the phtxt ...
>
Your code (snipped) has so much extra stuff going on (for example, you pass
in a handle and a pointer to the same block of memory, then unlock and
resize the handle, then lock it again and assign it to the original pointer)
that I just rewrote it entirely. Here is my code. (I'm sure someone
reading this would write the code differently, but this closely mirrors your
original code.)
// My version of hexdump, without hexHandle or slen params.
// Creates a hex version of stxt, and returns it in hextxt.
static void hexdump(Char* stxt, Char* hextxt)
{
MemHandle hhnd;
Char* htxt;
Int16 i, slen;
Char hs[] = "0123456789ABCDEF";
if (!stxt || StrLen(stxt) == 0)
StrCopy(hextxt, "");
else {
slen = StrLen(stxt);
hhnd = MemHandleNew(slen ? 3*(slen+1) : 1);
htxt = (Char *)MemHandleLock(hhnd);
for(i=0;i<slen;++i) {
htxt[3*i] = hs[((unsigned char)stxt[i])>>4];
htxt[3*i+1] = hs[((unsigned char)stxt[i])&15];
htxt[3*i+2] = ' ';
}
if (slen)
htxt[3*i-1] = '\0';
else
htxt[0] = '\0';
StrCopy(hextxt, htxt);
MemHandleUnlock(hhnd);
MemHandleFree(hhnd);
}
}
// code to call hexdump
static void myTest(void)
{
Char *phtxt, *ptxt;
UInt16 plen;
MemHandle phandle;
ptxt = "123456789";
// get space for the hex string
plen = StrLen(ptxt);
phandle = MemHandleNew(plen*3+1);
phtxt = (Char*) MemHandleLock(phandle);
hexdump(ptxt, phtxt);
FrmCustomAlert(MyAlertAlert, "crypto() - 5", ptxt, " ");
FrmCustomAlert(MyAlertAlert,"crypto() - 10", " ", phtxt);
MemHandleUnlock(phandle);
MemHandleFree(phandle);
}
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