Hi all 2 questions: 1. Is this constract: /something$[^x]somethingelse/m available in Perl as well? 2. Why should this constract match something\nsomethingelse I ask the question because \n does consume one position. I understand that the $ itself does not consume any position, but in that case why do we need it, since /something[^x]somethingelse/m should hapily match something\nsomethingelse as well. In essence, I guess that my question is what is the function of the $ assertion when not signaling the start of a string?
Ze'ev Atlas -- ## List details at https://lists.exim.org/mailman/listinfo/pcre-dev
