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http://bugs.exim.org/show_bug.cgi?id=1315




--- Comment #7 from Zoltan Herczeg <[email protected]>  2012-11-09 13:18:50 
---
> This pattern does that:   \r(?<!\n)

I think Philip wanted a forward assertion, not a backward, since this pattern
search for a \r character, and moves the position by one character ahead, and
checks that the last character is not \n, which is always true (\r != \n).

The correct form of this patern is: \r(?!\n)


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