On Mon, 2007-01-15 at 05:51 +0000, Claude Heiland-Allen wrote: > Roman Haefeli wrote: > > On Sun, 2007-01-14 at 15:01 +0000, Claude Heiland-Allen wrote: > >> When writing it I found a bug in wrap~ in pd-0.40-2 from Miller's site: > >> > >> sig~ 1 > >> wrap~ > >> print~ > >> -> 0 > > > > as i would expect. > > > >> sig~ 0 > >> wrap~ > >> print~ > >> -> 1 > > > > as i would expect, as well. where is the bug? am i missing something? > > wrap~-help says: > > ----8<---- > wrap~ gives the difference between the input and the > largest integer not exceeding it (for positive numbers this > is the fractional part). > ----8<---- > > largest integer not exceeding 0 is 0, or? > > largest integer not exceeding X is X when X is an integer, or?
exactly, and since [wrap~] gives you the difference between the largest integer not exceeding X and X, it will always give you 0, when X is an integer. the output of [wrap~] is always => 0 and < 1. > > it makes life simpler when > > (x - (wrap~ x)) == x > > when x is an integer, as there is no [int~] in Pd. i can't quite follow, what you mean hear. you CAN use [wrap~] to build your own [int~] (see attached patch). roman
#N canvas 754 157 222 270 10; #X obj 58 138 wrap~; #X obj 42 51 sig~; #X obj 41 164 -~; #X obj 41 197 avg~; #X floatatom 41 219 5 0 0 0 - - -; #X floatatom 42 25 5 0 0 0 - - -; #X connect 0 0 2 1; #X connect 1 0 0 0; #X connect 1 0 2 0; #X connect 2 0 3 0; #X connect 3 0 4 0; #X connect 5 0 1 0;
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