Hi, Just realised putting a negative number into the [pow] object outputs '0'?!?
For example if I do: [-1 ( | [pow 2] it returns 0, where I would expect it to return 1. Is this a known limitation or bug? Are there any work arounds if I want a variable power? (I'm running Pd 0.44.1 on OS X Mountain Lion) Thanks, Joe
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