On 10/16/2015 03:50 AM, Matt Barber wrote: > Basically, for [block~] sizes less than 32 bits, [fft~] doesn't perform -- > it just passes the signal through unchanged.
isn't that what is expected of a 1 point FFT? (32bits == 4 bytes == sizeof(float)). > See the attached patch, which only shows [fft~]. The saved contents of the > tables on opening are the results for [block~ 8] on my machine, for > quarter-nyquist at 44100. so you meant 32 bytes (8 samples * 4 bytes each)? or 32pins aka points (as in [block~ 32])? gfmrdsa IOhannes
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