connect output of [phasor~] into: [fexpr~ abs($x[0] - $x[-1]) > 0.5]
then use: [threshold~ 0.5 0 0.5 0] Em sáb, 2 de mar de 2019 às 11:05, Claude Heiland-Allen <[email protected]> escreveu: > On 2019-03-02 13:20, Orm Finnendahl wrote: > > is there some easy way in vanilla pd to get a bang on each phasor~ > > wraparound which doesn't involve polling with snapshot~? > > https://lists.puredata.info/pipermail/pd-list/2006-12/044634.html > > -- > https://mathr.co.uk > > > > _______________________________________________ > [email protected] mailing list > UNSUBSCRIBE and account-management -> > https://lists.puredata.info/listinfo/pd-list >
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