JC OCONNELL <[email protected]> wrote: > Typically, 0 dB represents 1 mW (milliWatt).
This is only the case with dBm where 0 dBm is indeed 1 mW across 600 Ohm, corresponding to a voltage of 0.775 V. dB with nothing behind expresses any kind of logarithmic ratio. Amplification, attenuation, signal-to-noise, whatever. You could define the price of a K-5 as 0 dB and then give the prices of all other cameras as plus (or minus) x dB. A camera costing +6 dB would be twice as expensive. -6 dB would be half price etc. Faders in studio equipment, e.g. mixing consoles, are usually labelled from minus infinity through 0 dB (the normal "open" position) to +15 dB. I suppose the manufacturer of the amplifier has put these dB values around the volume knob to make it look more professional. But don't take my word for it. I'm just a simple audio engineer. ;-) Ralf -- Ralf R. Radermacher - DL9KCG - Köln/Cologne, Germany Blog : http://the-real-fotoralf.blogspot.com Audio : http://aporee.org/maps/projects/fotoralf Web : http://www.fotoralf.de -- PDML Pentax-Discuss Mail List [email protected] http://pdml.net/mailman/listinfo/pdml_pdml.net to UNSUBSCRIBE from the PDML, please visit the link directly above and follow the directions.
