Hi All, How do I use chr inside a regex. In the below, how do I get rid of $y?
$ p6 'my Str $x=chr(0x66)~chr(0x77); my Str $y=chr(0x66)~chr(0x77); $x~~s/ $y /xy/; say $x;'
xy Many thanks, -T
Hi All, How do I use chr inside a regex. In the below, how do I get rid of $y?
$ p6 'my Str $x=chr(0x66)~chr(0x77); my Str $y=chr(0x66)~chr(0x77); $x~~s/ $y /xy/; say $x;'
xy Many thanks, -T