On 2/1/19 11:32 PM, JJ Merelo wrote:
Hi,
El sáb., 2 feb. 2019 a las 7:48, ToddAndMargo via perl6-users
(<perl6-us...@perl.org <mailto:perl6-us...@perl.org>>) escribió:
Hi All,
How do I use chr inside a regex. In the below, how
do I get rid of $y?
$ p6 'my Str $x=chr(0x66)~chr(0x77); my Str $y=chr(0x66)~chr(0x77);
$x~~s/ $y /xy/; say $x;'
If what you want to do is precisely what you are doing, you don't even
need to use chr:
my $x = "\x66\x77"; $x ~~ s/\x66\x77/xy/; say $x # OUTPUT: «xy»
(See the document on quoting:
https://docs.perl6.org/language/quoting#Interpolation:_qq)
However, if what you want to do is what you _say_ you are doing,
my $x = "\x66\x77"; $x ~~ s/$(chr(0x66)~chr(0x77))/xy/; say $x; #
OUTPUT: «xy»
$() interpolates within a regex, as indicated in the documentation:
https://docs.perl6.org/language/regexes#index-entry-regex__Regex_Interpolation-Regex_interpolation
Cheers
JJ
Thank you!
