On Mon, Jun 08, 2020 at 12:26:42AM +0300, Peter Pentchev wrote: > On Mon, Jun 08, 2020 at 12:21:22AM +0300, Peter Pentchev wrote: > > On Sun, Jun 07, 2020 at 01:57:11PM -0700, ToddAndMargo via perl6-users > > wrote: > > > On 2020-06-07 13:53, Peter Pentchev wrote: > > > > $path = 'lib1'.IO.d ?? 'lib1' !! 'lib2'; > > > > > > Got it! Thank you! > > > > > > I am not seeing the above enter the proper syntax: > > > > > > 'lib1', 'lib2' etc. > > > > > > Where is the comma? How are the single quotes entered? > > > > I don't understand what you are asking. The above checks whether > > a directory exists and, depending on the result of this check, assigns > > one of two values to a variable. I don't know what comma you are talking > > about. > > Wait, I think I got it. You're asking about the line underneath, the one > that you did not quote in this message, the line that says: > > use lib $path; > > "use lib" expects you to pass a string (or more strings). 'c:/NtUtil' is > a string. $path is a variable that holds a string. "use lib $path" > calls "use lib" and passes to it the string in the variable $path.
So to be a bit more clear, in your case you have a path that you always
need to pass ('c:/something') and another one that you want to pass only
if it exists. OK, so maybe something like:
my @path;
BEGIN {
for ('K:/NtUtil', 'X:/NtUtil') -> $candidate {
push @path, $candidate if $candidate.IO.d;
}
push @path, 'C:/NtUtil';
}
use lib @path;
Maybe something like that will work for you.
G'luck,
Peter
--
Peter Pentchev r...@ringlet.net r...@debian.org p...@storpool.com
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