From: Bob Rogers <[EMAIL PROTECTED]>
Date: Sun, 6 Apr 2008 13:25:33 -0400
From: chromatic <[EMAIL PROTECTED]>
Date: Sun, 6 Apr 2008 09:52:34 -0700
... compounded by the fact that I can't seem to get any of the existing
namespace ops to do what I want in a concise, non-hacky way. What am I
missing?
I notice that changing "get_root_namespace" to "get_hll_namespace" makes
the code you posted work. That seems completely backwards, though, so I
can't say that I understand it either . . .
Aha! It's because they're both in the default "HLL", the namespace for
which is called "parrot". So this also works:
test_namespace = get_root_namespace [ 'parrot'; 'Test'; 'More' ]
Not sure if that's any more intuitive, though.
-- Bob
