On Sun, Apr 6, 2008 at 10:30 AM, Bob Rogers
<[EMAIL PROTECTED]> wrote:
> From: Bob Rogers <[EMAIL PROTECTED]>
> Date: Sun, 6 Apr 2008 13:25:33 -0400
>
>
>
> From: chromatic <[EMAIL PROTECTED]>
> Date: Sun, 6 Apr 2008 09:52:34 -0700
>
> ... compounded by the fact that I can't seem to get any of the existing
> namespace ops to do what I want in a concise, non-hacky way. What am I
> missing?
>
> I notice that changing "get_root_namespace" to "get_hll_namespace" makes
> the code you posted work. That seems completely backwards, though, so I
> can't say that I understand it either . . .
>
> Aha! It's because they're both in the default "HLL", the namespace for
> which is called "parrot". So this also works:
>
> test_namespace = get_root_namespace [ 'parrot'; 'Test'; 'More' ]
>
> Not sure if that's any more intuitive, though.
>
by default, everything you write in pir is in the [ 'parrot' ] hll
namespace. therefore,
get_root_namespace [ 'parrot', 'Foo' ]
is equivalent to
get_hll_namespace [ 'Foo' ]
unless there's been a previous HLL directive for the non-default hll.
clear as mud?
~jerry
